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Converting a random epoch time into a readable format

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# 1  
Old 03-16-2014
Converting a random epoch time into a readable format
I am trying to create a script that will take epoch (input from command line) and convert it into a readable format in bash/shell

---------- Post updated at 08:03 PM ---------- Previous update was at 07:59 PM ----------
Code:
#!bin/bash

read -p "Please enter a number to represent epoch time:" STRING
echo "The UNIX time for $STRING is ($(($date -d "$STRING" + %m-%d-%Y %T utc)"

Last edited by Scott; 03-16-2014 at 10:26 PM.. Reason: Please use code tags
# 2  
Old 03-16-2014
@ feature present since GNU coreutils 5.3.0
Code:
date -d@"$STRING"

# 3  
Old 03-16-2014
When I ran the code with the @ symbol - it returns

date: invalid date '@String'

should I rename STRING to something else? or am I missing a parameter with this code? I took a scripting class but it was years ago and I cannot find anything online. Smilie
# 4  
Old 03-17-2014
Show us what exactly you did?
# 5  
Old 03-17-2014
Code:
#!/bin/bash

read -p "Please enter a number to represent epoch time:" STRING
echo "The UNIX time for $STRING is (date -d@$"STRING" +%m-%d-%Y %T -utc)"

Output: Please enter a number to represent epoch time:34565444
The UNIX time for 34565444 is (date -d@$STRING +%m-%d-%Y %T -utc)

Last edited by Don Cragun; 03-17-2014 at 04:20 PM.. Reason: Fix CODE tags.
# 6  
Old 03-17-2014
$"STRING" is wrong, try "$STRING"
# 7  
Old 03-17-2014
I did that but still received the same output, so:

I tried this:
Code:
#!/bin/bash

read -p "Please enter a number to represent epoch time:" STRING
echo "The UNIX time for $STRING is:" $($((date -d@"$STRING" +%m-%d-%Y %T -utc)))

The output was:

Code:
Please enter a number to represent epoch time:3456543
./test1.bash:  line 4: date -d@"3456543" +%m-%d-%Y %T -utc: syntax error: invalid  arithmetic operator (error token is "@"3456543" +%m-%d-%Y %T -utc")
The UNIX time for 3456543 is:

Last edited by Don Cragun; 03-17-2014 at 04:22 PM.. Reason: Add CODE tags.
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