Shell Programming and Scripting

Hi Experts ,

I have scheduled a script "createstructure "in crontab. The script runs every month on 25th .
I am trying to pass the input to the script as the <year><previousmonth>.For example ,if it is running in the month of March 2014 ,the input should be "201402" (2014-year 02-previous month ).For Jan 2015 , the input should be 201412.

Code:

 ./createstructure 201402 -->if running in the month of march.

Running Red Hat Enterprise in the server.

Is it doable ?


Thanks

Code:

dt=$(echo "$(date --date="1 month ago" +%Y%m)")
./createstructure $(echo $dt)

Great..Thanks a lot in2nix4life..

It would be helpful for me if you could just split and explain the command.

Thanks again..

That's an awful lot of useless echoes... You can boil this whole thing down to

Code:

./createstructure "$(date --date="1 month ago" +%Y%m)"

dt=$(date --date="1 month ago" +%Y%m) is sufficient

Code:

       -d, --date=STRING
              display time described by STRING, not `now'

So, 1 month ago tells date command to fetch the date that is 1 month ago in the format %Y%m (%Y --> 2014; %m --> 02)

Also, you could say "-1 month" -> minus has the same effect as ago

But on executing this "$(date --date="1 month ago" +%Y%m)" it is giving

$ "$(date --date="1 month ago" +%Y%m)"
-bash: 201402: command not found

In KSH93:

Code:

#!/bin/ksh93

LM=$( printf "%(%Y%m)T" "last month" )

./createstructure "$LM"