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How to delete line number 3,6,9,12,15 and so on?

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# 1  
Old 03-11-2014
How to delete line number 3,6,9,12,15 and so on?
Hello,

How can I remove line number 3,6,9,12,15,18 and so on for a text file using sed? The line number pattern is multiple 3.

Thanks in advance.
# 2  
Old 03-11-2014
Code:
awk 'NR%3' file

These 2 Users Gave Thanks to Yoda For This Post:
huiyee1 Scrutinizer
# 3  
Old 03-11-2014
You mean the line or the line numbers?
# 4  
Old 03-11-2014
Code:
sed 'n;n;d' file

GNU sed:
Code:
sed 0~3d file

This User Gave Thanks to Scrutinizer For This Post:
huiyee1
# 5  
Old 03-12-2014
Quote:
Originally Posted by ahamed101
You mean the line or the line numbers?
Dear ahamed101,

I mean 3rd, 6th, 9th, 12th, 15th line and so on. Thanks. It is solved.
Last edited by huiyee1; 03-12-2014 at 04:10 AM.. Reason: typo mistake
# 6  
Old 03-12-2014
Code:
awk ' NR/3 ~ /\./ ' file

This User Gave Thanks to anbu23 For This Post:
Scrutinizer
# 7  
Old 03-12-2014
@anbu: Novel approach, to force the number into string context. It brings with it, however, that it is implementation dependent whether locale is used to convert it and whether a "." is part of the string..

In BSD awk, for example it will not work with the wrong locale:
Code:
$ printf "%s\n" {1..17} | LC_NUMERIC=nl_NL awk ' NR/3 ~ /\./ '
$

Code:
$ printf "%s\n" {1..17} | LC_NUMERIC=en_US awk ' NR/3 ~ /\./ '
1
2
4
5
7
8
10
11
13
14
16
17

Last edited by Scrutinizer; 03-12-2014 at 04:17 AM..
This User Gave Thanks to Scrutinizer For This Post:
anbu23
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