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File processing

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# 1  
Old 03-07-2014
File processing
Hi,

I have a file
Code:
2013-01-01
2013-01-02
01-03-2013
03-03-2013
mar05

I need all the dates YYYY-MM-DD in a separate file and rest of the things in different file.

File 1:
Code:
2013-01-01
2013-01-02

File 2:
Code:
01-03-2013
03-03-2013
mar05

# 2  
Old 03-07-2014
Ok. Where are you stuck with your script?

--ahamed
# 3  
Old 03-08-2014
I used
Code:
grep -E '[0-9]{4}-[0-9]{2}-[0-9]{2}' test.txt

could get the first output file.

but I am not sure whether the second is date or month. I need exactly the month ie YYYY-MM-DD format to first file.

I am not sure on how to get the second output file
# 4  
Old 03-08-2014
Good!!

Now use -v along with your grep command to get the second output.
Do read the man page to understand what -v does.

--ahamed
# 5  
Old 03-08-2014
I used
test.txt
Code:
2013-01-01
2013-03-03
mar94
99-39034
03-40-2930

Code:
--> grep -v '[0-9]{4}-[0-9]{2}-[0-9]{2}' test.txt
2013-01-01
2013-03-03
mar94
99-39034
03-40-2930

Code:
--> grep -E '[0-9]{4}-[0-9]{2}-[0-9]{2}' test.txt
2013-01-01
2013-03-03

can you please let me know where I am going wrong
# 6  
Old 03-08-2014
For the second output, use both -E and -v option.
Code:
 grep -Ev '[0-9]{4}-[0-9]{2}-[0-9]{2}' test.txt

Code:
 man grep
        -v, --invert-match
              Invert the sense of matching, to select non-matching lines.  (-v is specified by POSIX.)

--ahamed
# 7  
Old 03-08-2014
Thank you
That worked fine for the second file.

I still have one issue left. In the first file I need only YYYY-MM-DD. But since the dates can be YYYY-DD-MM also . I am using [0-9]{2}-[0-9]{2} so either of the pattern can match. But I need only YYYY-MM-DD.
Can you please guide me
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