sed error in UNIX but not Linux

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# 1  
Old 03-07-2014
sed error in UNIX but not Linux

I was using the following code successfully on a linux system.
while read pattern; do
  grep -q $pattern en.pep
  if [ $? -ne 0 ]; then continue; fi
  line_number=`grep -m 1 -n $pattern en.pep | cut -f 1 -d :`
  echo ">$pattern"
  sed -n "$line_number { n; p; q}" en.pep
done < file1 > en_peps

But when I run it on unix I get the following error repeated many times with different line (?) numbers. Needless to say this error is not giving me much of a clue (I'm not much of a programmer), and all forum posts I've found were resolved in specific ways that don't apply to my situation.
sed: 1: "3163 { n; p; q}": extra characters at the end of q command

If someone could shed some light for me I'd appreciate it!
# 2  
Old 03-07-2014
I think you're missing a semi-colon. Try this:
sed -n "$line_number { n; p; q;}" en.pep

This User Gave Thanks to Perderabo For This Post:
# 3  
Old 03-07-2014
Many Unix sed have bugs with semicolon - newline works better
sed -n "$line_number {
" en.pep

This User Gave Thanks to MadeInGermany For This Post:
# 4  
Old 03-08-2014
Thanks, both of these solutions worked.
# 5  
Old 03-08-2014
Originally Posted by MadeInGermany
Many Unix sed have bugs with semicolon - newline works better [..]
Those are not a bugs:
Historically, the sed ! and } editing commands did not permit multiple commands on a single line using a <semicolon> as a command delimiter. Implementations are permitted, but not required, to support this extension.
sed: rationale

Anyway, the OP's sed apparently does support the semicolon (as most seds do nowadays), but since } is a command, there should be a semicolon in front of it.
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