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Awk: Print count for column in a file using awk

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# 1  
Old 02-26-2014
Awk: Print count for column in a file using awk
Hi,
I have the following input in a file & need output as mentioned below(need counter of every occurance of field which is to be increased by 1).

Input:
Code:
919143110065
919143110065
919143110052
918648846132
919143110012
918648873782
919143110152
919143110152
919143110152
919143110152

Output:
Code:
919143110065,1
919143110065,2
919143110052,1
918648846132,1
919143110012,1
918648873782,1
919143110152,2
919143110152,3
919143110152,4
919143110152,5

present code which needs modification is as follows(it counts the uniq count). Please help
Code:
awk 'count[$1]++}END{for (i in count) print i","count[i]}' input

# 2  
Old 02-26-2014
Code:
awk ' { arr[$0]++; print $0 "," arr[$0] } ' input

This User Gave Thanks to anbu23 For This Post:
siramitsharma
# 3  
Old 02-26-2014
I would simplify like this
Code:
$ awk '{print $0,++a[$0]}' file

This User Gave Thanks to Akshay Hegde For This Post:
siramitsharma
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