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[Solved] How can I pull specific information from PS?

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# 1  
Old 02-25-2014
[Solved] How can I pull specific information from PS?
I need to grab information from the output of the ps command.

For each line of ps output that contains
Code:
_progres -b

I need to get the word that follows
Code:
-p

. The "-p" can be anywhere after
Code:
"_progres -b"

.

Using grep to select the correct lines is no problem (e.g.
Code:
ps -ef|grep "_progres \-b|grep -v grep

). Or
Code:
ps -ef | awk ' /_progres \-b/ {print $0}'

. Although there maybe better ways.


It's what comes after that where I need some suggestions.

TIA Smilie
# 2  
Old 02-25-2014
Can you paste the output of the ps command?

May be something like this?
Code:
ps -eaf | awk '/_progres -b/{ gsub(/.*_progres -b.*-p/, x); print $1}'

--ahamed
Last edited by ahamed101; 02-25-2014 at 10:01 PM.. Reason: Updated code
# 3  
Old 02-25-2014
Try this:

Code:
 ps -ef | awk '/_[p]rogres /&&/-b/&&/-p / { gsub(/.* -p /, ""); print $1}'


Note with progress batch sessions, the -b can also appear anywhere on the line (even at the end):

Code:
chubler    17030 17024  0 02:02 ?        00:00:02 /usr/dlc/102b/bin/_progres -pf /u/learn/b2b.pf -p my-proc.p -param EFT=y -param TIMEOUT=1800 -b

Last edited by Chubler_XL; 02-25-2014 at 09:44 PM.. Reason: Provide good ps example
# 4  
Old 02-26-2014
Thanks to both of you for the replies.

Chubler, thanks for the reminder the -b can appear anywhere as well.

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