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Execution problem with print out record that follow specific pattern

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# 1  
Old 02-25-2014
Execution problem with print out record that follow specific pattern
Hi,

Do anybody know how to print out only those record that column 1 is "a" , then followed by "b"?
Input file :
Code:
a       comp92  2404242 2405172
b       comp92  2405303 2406323
b       comp92  2408786 2410278
a       comp92  2410271 2410337
a       comp87  1239833 1240418
b       comp87  1240496 1240829
b       comp87  1241046 1243683
a       comp87  1243841 1244840
a       comp87  1243841 1244840
b       comp87  1244968 1246522

Output file :
Code:
a       comp92  2404242 2405172
b       comp92  2405303 2406323
a       comp87  1239833 1240418
b       comp87  1240496 1240829
a       comp87  1243841 1244840
b       comp87  1244968 1246522

Thanks.
This User Gave Thanks to patrick87 For This Post:
Lucas_0418
# 2  
Old 02-25-2014
Hi guy,
Try this:
Code:
sed -n '/^a[[:blank:]]\{1,\}/{N;/\nb[[:blank:]]\{1,\}/p;D}'

cheers.
These 2 Users Gave Thanks to Lucas_0418 For This Post:
patrick87 Scrutinizer
# 3  
Old 02-25-2014
Awk approach with fixed strings:
Code:
awk '$1=="b" && k=="a" {print p ORS $0}{p=$0; k=$1}' file


--
@lucas: nice sed. \{1,\} can be left out, no?


*edit* it could also be done like this.
Code:
sed 'N;/^a[[:blank:]].*\nb[[:blank:]]/!D' file

Last edited by Scrutinizer; 02-25-2014 at 02:41 AM..
These 2 Users Gave Thanks to Scrutinizer For This Post:
Lucas_0418 patrick87
# 4  
Old 02-25-2014
Hi Scrutinizer,
Thanks Scurtinizer, thanks for your advice.
\{1,\} is not nessesary, a [[:blank:]] is totally enough, the sed code is better after you edited it.
This User Gave Thanks to Lucas_0418 For This Post:
patrick87
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