Aggregate variables bdfore ssh into remote host


 
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# 1  
Old 02-17-2014
Aggregate variables bdfore ssh into remote host

Hi all,

I have a problem where i'm trying to identify on which remote hosts the apps are running, ssh into it and restart them.

In case more than 1 apps is running on same remote host, i want to be able to group it and ssh only once.

E.g:

Code:
app1 = 1.1.1.1
app2 = 1.1.1.2
app3 = 1.1.1.1
app4 = 1.1.1.3

Any thoughts?

I have played with the arrays but couldn't figure out.

Thank you for your help.

---------- Post updated 02-17-14 at 09:39 AM ---------- Previous update was 02-16-14 at 11:56 PM ----------

the complexity is in that i don't want to do multiple if else for each permutations

Code:
app1 = app2
app1 = app3
app1 = app4
app2 = app3
app2 = app4
app3 = app4

Hope is not too hard to achieve it.

Last edited by Scott; 02-17-2014 at 01:45 PM.. Reason: Code tags
# 2  
Old 02-17-2014
Not sure if i understood correctly, but this may helps:
Code:
# awk  '{a[$NF]=sprintf("%s%s ",a[$NF],$1)}END{for (i in a){print i,a[i]}}' infile
1.1.1.1 app1 app3 
1.1.1.2 app2 
1.1.1.3 app4

This User Gave Thanks to Klashxx For This Post:
# 3  
Old 02-17-2014
Thanks a lot!

any chance you can explain the line, mainly the first part before the END?

---------- Post updated at 11:55 AM ---------- Previous update was at 11:43 AM ----------

No need as i figured out,

thanks again !!

---------- Post updated at 05:42 PM ---------- Previous update was at 11:55 AM ----------

Quote:
Originally Posted by Klashxx
Not sure if i understood correctly, but this may helps:
Code:
# awk  '{a[$NF]=sprintf("%s%s ",a[$NF],$1)}END{for (i in a){print i,a[i]}}' infile
1.1.1.1 app1 app3 
1.1.1.2 app2 
1.1.1.3 app4


One more question please ...

for the above code, is it possible to write it to unique file based on the first argument - in our case i ?

e.g

Code:
1.1.1.1 app1 app3 > 1.1.1.1_txt
1.1.1.2 app2 > 1.1.1.2_txt
1.1.1.3 app4 > 1.1.1.3_txt

Thx

Last edited by Scott; 02-17-2014 at 01:46 PM.. Reason: Code tags
# 4  
Old 02-17-2014
Code:
awk '
        {
                A[$NF] = A[$NF] ? A[$NF] FS $1 : $1
        }
        END {
                for ( k in A )
                        print k, A[k] > k "_txt"
        }
' file

# 5  
Old 02-18-2014
If you want to use the same script:
Code:
awk  '{a[$NF]=sprintf("%s%s ",a[$NF],$1)}END{for (i in a){print i,a[i] > i"_txt"} }' infile

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