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How to grep only some part of character?

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# 1  
Old 02-06-2014
How to grep only some part of character?
Hi,

I have log :

Code:
# cat log

[~/temp]$ cat 4
2014092014
2014102014
2014112023
2014123014
2014010100
2014010101
2014010102
2014010103
2014010104
2014020123
2014020115
2014020116
2014020117
2014020118
2014020119
2014020120
2014020121
2014020122
2014020123
2014020200
2014020201
2014030202
2014033203
2014030204
2014030205
2014030206
2014030207
2014030208
2014030223
2014030210
2014030211
2014030212
2014030213

I want only grep 2014xxxx23 ?

Code:
2014112023
2014020123
2014020123
2014030223

# 2  
Old 02-06-2014
Code:
grep 2014[0-9][0-9][0-9][0-9]23 file

This User Gave Thanks to PikK45 For This Post:
justbow
# 3  
Old 02-06-2014
Quote:
Originally Posted by justbow
Hi,
....
I want only grep 2014xxxx23 ?
....
Code:
$ grep  -E '2014[[:digit:]]{4}23' file
2014112023
2014020123
2014020123
2014030223

This User Gave Thanks to Akshay Hegde For This Post:
justbow
# 4  
Old 02-06-2014
As long as you know that you're only working with numeric input, a simpler approach is:
Code:
grep '2014....23' file

This User Gave Thanks to Don Cragun For This Post:
justbow
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