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[Solved] Replace character in 3rd column and leave 1rst and last

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Top Forums Shell Programming and Scripting [Solved] Replace character in 3rd column and leave 1rst and last
# 1  
Old 02-01-2014
[Solved] Replace character in 3rd column and leave 1rst and last
Hello to all,

I have the following text where columns are separated by spaces. I want to have the 3rd column separating
3 strings with 2 "_" in the format below:

LeftSring_CentralString_RightString

So, in 3rd column I want to replace all "_" with "-", except the first and last "_"

The input file is (in red "_" that should be replaced):
Code:
573839 12737 XFFK_UUD-KKDD_JDUDU_PPWI28
24300123 9927827 LUUUEO_OP-MJJF_JJI98_5526_TTTKC
4429999 988601 UDDYDYY_AAAABBNV_RWYYY
7878 92222 HHDRR_IPd.koo_ljjdLPP-IIDUUDD.OPPE_T23JJK

and the output desired (in orange new character "-"):
Code:
573839 12737 XFFK_UUD-KKDD-JDUDU_PPWI28
24300123 9927827 LUUUEO_OP-MJJF-JJI98-5526_TTTKC
4429999 988601 UDDYDYY_AAAABBNV_RWYYY
7878 92222 HHDRR_IPd.koo-ljjdLPP-IIDUUDD.OPPE_T23JJK

May somebody help to do this with awk or sed?

Thanks in advance
# 2  
Old 02-01-2014
What have you tried?
# 3  
Old 02-03-2014
Hello Don,

Sorry for my late response. I've tried with gensub as below, but is replacing all "_" with "-" in 3rd column
and I don't want to replace the first "_" and last "_", only replace from the 2nd underscore to n-1 underscore.

Code tried:
Code:
awk '{print $1, $2, gensub(/_/,"-",g,$3) }'
573839 12737 XFFK-UUD-KKDD-JDUDU-PPWI28
24300123 9927827 LUUUEO-OP-MJJF-JJI98-5526-TTTKC
4429999 988601 UDDYDYY-AAAABBNV-RWYYY
7878 92222 HHDRR-IPd.koo-ljjdLPP-IIDUUDD.OPPE-T23JJK

For the output I'm getting above, the dashes in red should not be replaced from underscore to dash. The output desired below:
Code:
573839 12737 XFFK_UUD-KKDD-JDUDU_PPWI28
24300123 9927827 LUUUEO_OP-MJJF-JJI98-5526_TTTKC
4429999 988601 UDDYDYY_AAAABBNV_RWYYY
7878 92222 HHDRR_IPd.koo-ljjdLPP-IIDUUDD.OPPE_T23JJK

Maybe someone could help me with this.

Thanks
# 4  
Old 02-03-2014
Code:
$ awk -F"_" ' { printf("%s",$1 FS $2);for(i=3;i<NF;i++) printf("%s","-"$i); printf("%s\n",FS NF) } ' file
573839 12737 XFFK_UUD-KKDD-JDUDU_4
24300123 9927827 LUUUEO_OP-MJJF-JJI98-5526_5
4429999 988601 UDDYDYY_AAAABBNV_3
7878 92222 HHDRR_IPd.koo-ljjdLPP-IIDUUDD.OPPE_4

This User Gave Thanks to anbu23 For This Post:
Ophiuchus
# 5  
Old 02-03-2014
I'm not familiar with gensub(). Assuming that there are at least 2 underscores in field 3, you could try something like:
Code:
awk '
{       n = split($3, x, /_/)
        printf("%s %s %s_", $1, $2, x[1])
        for(i = 2; i <= n; i++)
                printf("%s%s", x[i], i == n ? "\n" : i == (n - 1) ? "_" : "-")
}' input

This should work even if there are underscores in field 1 or field 2.

If there will never be any underscores in field 1 or field 2 and there are at least two underscores in field 3, anbu23's suggestion should also work if you change the last printf from printf("%s\n",FS NF) to printf("%s\n",FS $NF).

If you want to run either of these script on a Solaris/SunOS system, use /usr/xpg4/bin/awk, /usr/xpg6/bin/awk, or nawk instead of the default /usr/bin/awk.
This User Gave Thanks to Don Cragun For This Post:
Ophiuchus
# 6  
Old 02-03-2014
Thanks so much anbu23 and Don for your solution and fix anbu´s code. It worked so nice!

Regards
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