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Get Previous day error from alertlog

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# 1  
Old 01-27-2014
Get Previous day error from alertlog
Hi All,

I want to get the all ORA- related errors from attached logfile for previous day. Pls help. Thanks !

Regards
Kamal
alertlog_sample.txt (2.7 KB) 
# 2  
Old 01-27-2014
Quote:
Originally Posted by kamauv234
I want to get the all ORA- related errors from attached logfile for previous day
Going by your requirement, a simple grep would suffice?
Code:
grep ORA alertlog_sample.txt

# 3  
Old 01-27-2014
Thanks for the reply. simple grep statement will collect all the ORA- errors from alertlog file (Contains all records) .. But I need only previous day ORA- errors ...
# 4  
Old 01-27-2014
This quick dirty one liner would look for previous day pattern (as given in the sample) and start reading till the end.
Code:
awk -v p="$(date --date '1 day ago' +'%a %b %d')" '$0 ~ p {f=1} f==1 && /ORA-/ {print}' alert_log_file


Does your script run daily ? or multiple times in a day?

I think, you don't want to repeat the alert if you already did. If that's your requirement, then you can probably do something like,

- Read the file
- Grep for errors and store the last_line_no somewhere.
- Next time read the file after the last_line_no.
- Since, alert_log file can be archived too, so need to handle the following simple case,

Code:
if ( last_line_no > total_current_lines ) {
  # new alert_log file
  # last_line=0
} else {
  # normal processing
}

Hope it helps
# 5  
Old 01-27-2014
Thanks for the reply. I am getting below error while using the above code

Code:
$ awk -v p="$(date --date '1 day ago' +'%a %b %d')" '$0 ~ p {f=1} f==1 && /ORA-/ {print}' alert_APDSPRD.log
date: illegal option -- date
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]
awk: syntax error near line 1
awk: bailing out near line 1

Code:
$ uname -a
SunOS sgaygipora100 5.10 Generic_150400-03 sun4v sparc sun4v

Last edited by Scrutinizer; 01-28-2014 at 03:12 AM.. Reason: code tags
# 6  
Old 01-28-2014
You don't have GNU date. For non GNU, I have found this quick alternative. Try if that works

Code:
awk -v p="$(TZ=GMT+24; date +'%a %b %d')" '$0 ~ p {f=1} f==1 && /ORA-/ {print}' alert_APDSPRD.log

For a more robust solution, I suggest to use perl or search for various date arithmetic threads in this forum.
# 7  
Old 01-28-2014
And on Solaris 10 use
Code:
/usr/xpg4/bin/awk

This User Gave Thanks to Scrutinizer For This Post:
clx
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