Formating questions


 
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Old 01-28-2014
Hello,

Following may also help, it will not see the the CHAR(2-20) it will only look CHAR( and accordingly will give as requested output.


Code:
awk '/CHAR\(1\)/ {print} !/CHAR\(1\)/ {gsub(/CHAR\(/,"VARCHAR\("); print}'  file_name


Output wil lbe as follows.

Code:
cur_rev_stage_cd VARCHAR(5) CHARACTER SET LATIN NOT CASESPECIFIC NOT NULL,
prev_rev_stage_cd VARCHAR(5) CHARACTER SET LATIN NOT CASESPECIFIC,
revrec_prcs_cd VARCHAR(2) CHARACTER SET LATIN NOT CASESPECIFIC,
revrec_cur_rev_stage_cd VARCHAR(5) CHARACTER SET LATIN NOT CASESPECIFIC,
revrec_prev_rev_stage_cd VARCHAR(5) CHARACTER SET LATIN NOT CASESPECIFIC,
svc_base_cd VARCHAR(2) CHARACTER SET LATIN NOT CASESPECIFIC,
pkging_type_cd VARCHAR(2) CHARACTER SET LATIN NOT CASESPECIFIC,
bus_tran_type_cd CHAR(1) CHARACTER SET LATIN NOT CASESPECIFIC,
dvc_nm VARCHAR(5) CHARACTER SET LATIN NOT CASESPECIFIC,
cust_intln_cd VARCHAR(3) CHARACTER SET LATIN NOT CASESPECIFIC,
cash_only_flg CHAR(1) CHARACTER SET LATIN NOT CASESPECIFIC,
shpmt_type_cd CHAR(1) CHARACTER SET LATIN NOT CASESPECIFIC,


Thanks,
R. Singh
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