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sed Command new Line not working Tried many variations

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# 1  
Old 01-19-2014
sed Command new Line not working Tried many variations
Hi

I have assigned an output of a command to $I. I try to print the input and put a new line after occurrence of the hostname which is assigned to $HOST1 ( Example: pwrm16 ) . First of all I need to get rid of the Colon after the host name pwrm16: and make it pwrm16 then I want to print the rest of the line until I hit another hostname. In short I need to get rid of the the colon before the host pwrm16: and then print the line from the string until I get to the next host name . Can someone please help me ? Tried my best and wasted a lot of times


***********************************
I want the output be in this format:


Code:
pwrm16: Info: Thu Dec 12 22:20:23 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition.

pwrm16: Info: Sun Dec 15 21:37:30 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition.

*****************************************

I can get rid of the colon by using tr and reassign it ti the variable. However
I just have not able to print anything on a new line. It just not working. I went on internet and tried everything I could find. Just don't seem able to print anything on a new line. Basically all I get is the entire string.

Current command I'm using ( used so many difference variations )
Code:
printf "$I "| sed 's/$HOST1/\n/g'
$HOST1 = pwrm16


*****************************************

Current output I get is as follow

Code:
pwrm16: Info: Thu Dec 12 22:20:23 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm17: Info: Sun Dec 15 21:37:30 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm18: Info: Wed Dec 18 11:31:43 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm16: Info: Wed Dec 18 14:00:05 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm16: Info: Thu Jan 02 13:51:24 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm19: Info: Fri Jan 17 01:16:26 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm16: Info: Fri Jan 17 03:39:19 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition.

********************************************
Last edited by Scrutinizer; 01-19-2014 at 04:39 PM..
# 2  
Old 01-19-2014
Quote:
Originally Posted by mnassiri
Current command I'm using ( used so many difference variations )
printf "$I "| sed 's/$HOST1/\n/g'
$HOST1 = pwrm16

First, the variable assignment should be:

Code:
HOST1=pwrm16  ## No $ and no spaces around =


Second, you don't need sed; use parameter expansion. For example:

Code:
var1=${i#*: ] ## the contents of the variable after the first ': '
var2=${i%%:*} ## The contents of the variable before the first colon

Last edited by cfajohnson; 01-19-2014 at 04:36 PM..
# 3  
Old 01-19-2014
Power
Try :
Code:
$ cat file
pwrm16: Info: Thu Dec 12 22:20:23 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm17: Info: Sun Dec 15 21:37:30 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm18: Info: Wed Dec 18 11:31:43 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm16: Info: Wed Dec 18 14:00:05 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm16: Info: Thu Jan 02 13:51:24 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm19: Info: Fri Jan 17 01:16:26 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. pwrm16: Info: Fri Jan 17 03:39:19 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition.

Code:
$ awk 'gsub(host_prefix,"\n\n&")' host_prefix=pwrm  file


pwrm16: Info: Thu Dec 12 22:20:23 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. 

pwrm17: Info: Sun Dec 15 21:37:30 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. 

pwrm18: Info: Wed Dec 18 11:31:43 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. 

pwrm16: Info: Wed Dec 18 14:00:05 2013 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. 

pwrm16: Info: Thu Jan 02 13:51:24 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. 

pwrm19: Info: Fri Jan 17 01:16:26 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition. 

pwrm16: Info: Fri Jan 17 03:39:19 2014 User PWPYNYFWD01 at position 170.198.8.160/net on host 170.198.8.160 using application 257 has been disconnected due to an overflow condition.

Code:
$ awk 'gsub(host_prefix,"\n\n&")' host_prefix=pwrm <<<$Variable

Last edited by Akshay Hegde; 01-19-2014 at 04:47 PM..
# 4  
Old 01-20-2014
Hi thanks for ur responses .. I will try these and get back to u when I get to work tomorrow .. I try to set a virtual host and try it now
good day

---------- Post updated at 02:52 PM ---------- Previous update was at 02:46 PM ----------

Ashkey Hedge .. I do not have a file to cat . I ssh to certain hosts and get that information from log file and assign it to A variable so I'm not sure what u mean bu catting the file? I can read the variable.

also the host . I'm not sure what you mean by this?
host prefix is pwrm and a number. It can be anything from pwrm01 through pwrm19 ..

awk 'gsub(host_prefix,"\n\n&")' host_prefix=pwrm <<<$Variable
so I'm not sure how this will work. Maybe I'm missing soething here but not sure what toi substitute the host_prefix with as it will change .?

# 5  
Old 01-20-2014
Hello,

Following may help you.

Code:
a=`echo "120|000000002|2PM||0|0098442940|0|0134515050|MOBILE 013|0||03|01|NL02||0|11|1|1|C|20130401175314|20130401175317|+0800|3|0|10|0||02|0|||M"`
echo $a | perl -ple 's/MOBILE/\n/'

Output will be as follows.

Code:
120|000000002|2PM||0|0098442940|0|0134515050|
 013|0||03|01|NL02||0|11|1|1|C|20130401175314|20130401175317|+0800|3|0|10|0||02|0|||M

It is just a simple example for changing a word with a new line for a variable.



Thanks,
R. Singh
# 6  
Old 01-20-2014
cfajohnson ,, Thanks for ur reply .. I just tested the reassignment of the variable and it works great. But please remember , I have to print everything after the hostname until the occurence of the next host name on a new line. You reply does not address my question in full though is very useful ...So the output should be.

my input is assigned to variable i is as follow :
hostname1: text goes here hostname2: text goes here hostname3: text goes here

The output should be:
hostname1 text here
hostname2 text here
hostname3 text here

---------- Post updated at 03:04 PM ---------- Previous update was at 03:01 PM ----------

Ravindersingh13 - Thanks for ur reply .. I appreciate the perl command. But I won;t be able to use it in this script. I need to use the shell command to do this. Can you help with a shell command:

my input is assigned to variable i is as follow :
hostname1: text goes here hostname2: text goes here hostname3: text goes here

The output should be:
hostname1 text here
hostname2 text here
hostname3 text here Image
# 7  
Old 01-20-2014
If your variable is "A" then use like this

Code:
$ awk '{for(i=1;i<=NF;i++)printf  i!=1 && $(i+1)~/Info:/ ? RS RS $i : i < NF ? $i FS : $i RS RS}' <<<$A


OR
Code:
$ echo $A |  awk '{for(i=1;i<=NF;i++)printf  i!=1 && $(i+1)~/Info:/ ? RS RS $i : i < NF ?  $i  FS : $i RS RS}'

Hope this would be fine for you.
Last edited by Akshay Hegde; 01-20-2014 at 05:40 PM..
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