Assignment with variable assigment

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# 1  
Old 12-21-2013
Assignment with variable assigment

Hello All,

I'm trying to assign integer values to variables using substitution in both the value and variable's name, i.e.,


where x is equal to one in the first assignment, two in the second assignment, and so on with x being incremented each time.

However, when I do the first assignment


the assignment works but I get

number1=1 not found.

what's going on?
Thank you in advance.

Last edited by bartus11; 12-21-2013 at 06:35 PM.. Reason: Please use code tags
# 2  
Old 12-21-2013
eval number$x=$x

# 3  
Old 12-22-2013
Rule: if you compose a string, and you want to run it, and it is other than a command name,then you need eval.

Last edited by MadeInGermany; 12-22-2013 at 03:23 AM.. Reason: precised
# 4  
Old 12-22-2013
What shell are you using? Does it have arrays:
echo "${number[x]}"

# 5  
Old 12-22-2013
Yes, I see that the eval command works.
However, the assignment also does work without eval.
But, I get that "not found" error.
What's going on there?
# 6  
Old 12-22-2013
Without eval the shell is trying to execute the command number1=1 which apparently is not present on your system so it says "not found"
# 7  
Old 12-22-2013
But why is the shell trying to execute a command?
Why is not performing assignment?
So, I'll ask once again, what's going on here?
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