Shell Programming and Scripting

Hello All,

I'm trying to assign integer values to variables using substitution in both the value and variable's name, i.e.,

Code:

number$x=$x

where x is equal to one in the first assignment, two in the second assignment, and so on with x being incremented each time.

However, when I do the first assignment

Code:

number$x=$x

the assignment works but I get

number1=1 not found.

what's going on?
Thank you in advance.

Try:

Code:

eval number$x=$x

Rule: if you compose a string, and you want to run it, and it is other than a command name,then you need eval.

What shell are you using? Does it have arrays:

Code:

number[x]=$x
echo "${number[x]}"

Yes, I see that the eval command works.
However, the assignment also does work without eval.
But, I get that "not found" error.
What's going on there?

Without eval the shell is trying to execute the command number1=1 which apparently is not present on your system so it says "not found"

Obviously.
But why is the shell trying to execute a command?
Why is not performing assignment?
So, I'll ask once again, what's going on here?