Bash - Nesting if statement in for loop


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# 1  
Bash - Nesting if statement in for loop

I have the basic command written in bash

Code:
 for element in 1 2
   do
    if [[ $element == '1' ]]; then
      set el = "t"
    else
      set el = "p"
    fi
    done

but i get the following error

Code:
syntax error near unexpected token `for'
`   for element in 1 2'

What should i do differently?
# 2  
to compare integer do like this

if [ "$element" -eq "1" ]; then

for string if [ "$element" == "1"]; then

Code:
for element in 1 2; do 
if [ "$element" == "1" ]; then
      el="p"
else
      el="t"
fi
done

it's good to use double quotes while comparing

Last edited by Akshay Hegde; 12-12-2013 at 10:30 AM..
This User Gave Thanks to Akshay Hegde For This Post:
# 3  
Running your snippet with set -vx in bash, I get
Code:
+ for element in 1 2
+ [[ 1 == \1 ]]
+ set el = t
+ for element in 1 2
+ [[ 2 == \1 ]]
+ set el = p

so - no error message, code behaves as expected. It there more/other lines before for that may interfere?
# 4  
Code:
for el in t p
do
    :
done

Smilie
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