awk regular expression search


 
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# 1  
Old 11-28-2013
awk regular expression search

Hi All,

I would like to search a regular expression by passing as an i/p variableto AWK.

For Example ::
Code:
162.111.101.209.9516 
162.111.101.209.41891
162.111.101.209.9516 
162.111.101.209.9517 
162.111.101.209.41918
162.111.101.209.9517 
162.111.101.209.41937
162.111.101.209.41951
162.111.101.209.41954

i would like to extract 9516 and 9517 i.e., pattern 951[1-9] only.

Below is the command i have tried which worked


Code:
cat File | awk -F. ' $NF ~ /951[1-9]/ {print $0 }'


But i would like to pass the search pattern as a variable. Can you please help me.

Last edited by Scott; 11-28-2013 at 07:26 AM.. Reason: Please use code tags for code and data
# 2  
Old 11-28-2013
Code:
awk -F. '$NF ~ p' p='951[1-9]' infile

# 3  
Old 11-28-2013
im working on netstat command.
can you please help me how to stream the output to above command
# 4  
Old 11-28-2013
netstat's output includes both local and foreign address, which one do you want?
# 5  
Old 11-28-2013
local address
# 6  
Old 11-28-2013
If the local address is in the first column (as on Solaris),
something like this might work:

Code:
netstat -anf inet | nawk '$1 ~ p' p='\.951[1-9]$'

If the above script errors out or doesn't produce the expected output,
post a sample of your netstat output.
What OS are you using?
# 7  
Old 11-28-2013
yes it is working. Thanks.
How about if i want to pass a variable instead of 951[1-9]
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