Get number of lines after certain string

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# 8  
Old 11-27-2013
awk '
               num = "one two three four five six seven eight nine ten"
                 n = split(num,A)
               if ((NUM[tolower($1)]-2)^2 == 1)
               printf "start,%d,%s,%s\n", NUM[tolower($1)], $2, $3
   ' file

If you are trying in Solaris/Sun OS use nawk
This User Gave Thanks to Akshay Hegde For This Post:
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