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[Solved] sed - how replace date in script

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# 1  
Old 11-27-2013
Question [Solved] sed - how replace date in script
Hi All,

I have a requirement to find and replace old date with new date value. Below is the scenario:

# In the input file, date is MM/DD/YYYY format

Code:
PREV_DTE=09/15/2013

I want to replace with 09/30/2013. It should look like

Code:
PREV_DTE=09/30/2013

I am using below sed command :

Code:
sed -e "s|PREV_DTE=|PREV_DTE=${PRE_DT_TO}|" < input_file > output_file

But the output i am getting is
Code:
PREV_DTE=09/15/201309/30/2013

Please help on how to achieve this !

Regards,
Last edited by Don Cragun; 11-27-2013 at 04:43 AM.. Reason: Add CODE tags.
# 2  
Old 11-27-2013
Hello,

It's a kind request please use code tags while posting queries.
Here is the following which may help you.

Code:
echo "09/15/2013" | awk -v new_date="09/30/2013" '(sub($0,new_date))'
09/30/2013


Thanks,
R. Singh
# 3  
Old 11-27-2013
Try:

Code:
$ date -d"09/15/2013 + 15 day" +%m/%d/%Y
09/30/2013

Code:
$ echo "09/15/2013" | awk '$1=Newdate' Newdate="09/30/2013"
09/30/2013

# 4  
Old 11-27-2013
Try:
Code:
sed -e "s|PREV_DTE=../../....|PREV_DTE=${PRE_DT_TO}|" < input_file > output_file

This User Gave Thanks to Don Cragun For This Post:
rockygsd
# 5  
Old 11-27-2013
Thanks Don Cragun ! It worked...
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