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Syntax error near unexpected token `|'

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# 1  
Old 11-26-2013
Syntax error near unexpected token `|'
Hi All;

I try to write a bash code and I am using command substitution. My code is like:

Code:
#!/bin/bash

IP="10.0.0.1 10.0.0.2"
PORT="22 80"
USERNAME="admin"
SCRIPT_HOST="adminHost"
HOME_DIR=/home/admin
SCRIPT_DIR=$HOME_DIR/scripts
script="sudo /my_remote_script.sh"
SSH="/usr/bin/ssh -t -o ConnectTimeout=10 -l ${USERNAME} ${SCRIPT_HOST}"

declare -a array1
declare -a array2
declare -a array3


for ip in ${IP}" ; do
    for port in ${PORT} ; do

        rmt_command1=" $script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' "

        rmt_command2=" $script -i $ip -p $port  | awk -v IGNORECASE=1 '/pattern2/ {print \$5}' "

        rmt_command3=" $script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern3/ {print \$5}' "

        array1[$ip,$port]=$($SSH "$rmt_command1")
        array2[$ip,$port]=$($SSH "$rmt_command2")
        array3[$ip,$port]=$($SSH "$rmt_command3")

    done
done

for ip in ${IP}
    
    for port in {PORT}
        printf   ${array1[$ip,$port]}
        printf   ${array2[$ip,$port]}
        printf   ${array3[$ip,$port]}

    done

done

And I receive an error message like:
Code:
./test_sh: line 20: syntax error near unexpected token `|'
./test_sh: line 20: `        rmt_command1=" $script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' "'

What could be wrong?
Last edited by Meacham12; 11-26-2013 at 06:02 AM..
# 2  
Old 11-26-2013
At first sight I already see a few problems:

Code:
for ip in "${IP}" ; do

Code:
for port in ${PORT} ; do

Code:
rmt_command1=" $script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' "

Where is the $script variable set?
Last edited by Subbeh; 11-26-2013 at 06:06 AM..
# 3  
Old 11-26-2013
Sorry I have 2 copies of same file $script was actually $remote_script. Neither worked. Corrected.
# 4  
Old 11-26-2013
I guess this must be your problem
change this
Code:
$ rmt_command1=" $script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' "
$ echo $rmt_command1
-i -p | awk -v IGNORECASE=1 '/pattern1/ {print $4}'

to
Code:
$ rmt_command1=" \$script -i \$ip -p \$port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' "
$ echo $rmt_command1
$script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print $4}'

Try and let me know..
# 5  
Old 11-26-2013
use backticks instead of double quotes if you want your script to be executed here:
Code:
`$script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' `

instead of

Code:
$script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}'

same for all those 3 lines.

i didnt see the error after the change.
# 6  
Old 11-26-2013
Quote:
Originally Posted by greet_sed
use backticks instead of double quotes if you want your script to be executed here:
Code:
`$script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}' `

instead of

Code:
$script -i $ip -p $port | awk -v IGNORECASE=1 '/pattern1/ {print \$4}'

same for all those 3 lines.

i didnt see the error after the change.
I don't think he wants the code executed there; it has to be run on the server which he makes an SSH connection to... Therefore, don't change the quotes.
This User Gave Thanks to Subbeh For This Post:
greet_sed
# 7  
Old 11-26-2013
Quote:
Originally Posted by Subbeh
At first sight I already see a few problems:

Code:
for ip in "${IP}" ; do

[CODE]
Do we need the quotes here? This will make the the value of ip as 10.0.0.1 10.0.0.2 instead of taking them one by one.

This would be better
Code:
for ip in ${IP} ; do

Last edited by chacko193; 11-26-2013 at 07:08 AM..
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