Value Too Great for Base Error, Explanation and Workout needed

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# 8  
Old 11-19-2013
Originally Posted by RudiC
bash takes numerical input with leading zeroes to be octal values, hence 8 & 9 are too great. You can either strip the zeroes or indicate the base by e.g. a leading 10# . man bash:
with this in mind

i would turn my variables to ??

    local_dtcmp=`date -d "$1" +"%F"`; shift
    local_dtcmp="$(( 10#$local_dtcmp ))"
    local_today=`date -d "$*" +"%F"`
    local_today="$(( 10#$local_today ))"
    return `test $((today - dtcmp)) -lt 0`

---------- Post updated at 06:50 PM ---------- Previous update was at 06:46 PM ----------

Originally Posted by Chubler_XL
Well try a file with 2013-02-02 timestamp and you'll set that code thinks that file is not old!

I tested it with a file with that time stamp and it worked fine.

the only issue I have seen so far is still with the 08 & 09 numbers

will try and convert yo base 10 with the 10# suggested earlier
# 9  
Old 11-19-2013
Apologies the issue asserts it's self when you look at recent dates eg: 2013-11-19
# 10  
Old 11-19-2013
no worries. in any case, i continued to use the 10# and was still unsuccessful.

i was told with the GNU Tools I can use date and do something like
date --date="7 days ago"

anyone know the validity of this?
# 11  
Old 11-20-2013
Yes that is perfectly valid for GNU date or you could do date --date "today - 7 days"
# 12  
Old 11-20-2013
This looks weird to me
return `test $((today - dtcmp)) -lt 0`

The return status is the exit status of the last command. Save a subshell and just end the function with

(( today - dtcmp < 0 ))

# 13  
Old 11-20-2013
The following does a string comparison what is IMHO more appropriate than integer comparison,
and implicitly returns the last status code (0 or 1):
    local dtcmp=`date -d "$1" +"%F"`; shift
    local today=`date -d "$*" +"%F"`
    [[ $today < $dtcmp ]]

GNU date is required anyway, regardless if "today -7 days" or "-7 days" or -d or --date
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