Shell Programming and Scripting

Hello Guys

I have a big list of files in one directory. And Some are missing .

Example
ls -l

Code:

2191off-r0.sps
2193off-r0.sps
2194off-r0.sps
2197off-r0.sps
2198off-r0.sps
2200off-r0.sps

I would like to create a file with the list only missing files. Or if is possible to create in
the same directory empty files

example
I should get the following files in the same directory.. Empty files. Or a List with the missing files.

Code:

2192off-r0.sps
2195off-r0.sps
2196off-r0.sps
2199off-r0.sps

Thanks a lot for your cooperation.

Try

Code:

for i in {2191..2200}off-r0.sps; do [ -f $i ] || echo $i; done

This is for the list; replace echo by touch (or redirection >) to create the files.

If you don't care about the modification times on those files, then this will create missing files as empty files:

Code:

for i in {2191..2200}; do touch "${i}off-r0.sps"; done

Alternative approach:

Code:

ls | awk '!/\.sps$/{next}{n=$1+0} p!=""{while(++p<n){sub(/^[0-9]*/,p); print}} {p=n}'

Thanks a lot to all