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UNIX comand

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# 1  
Old 11-14-2013
HP UNIX comand
Team,

I need unix command to grep directory part from the string
for example I have a texts something like
Code:
/apps/opt/data/current/spool/test.dbf
/apps/opt/archive/../../test.dbf

I need only directory part from that string
like my out put will

Code:
/apps/opt/data/current/spool/
/apps/opt/archive/../../

Code:
echo "/apps/opt/data/current/spool/test.dbf" | awk -F"/" '{ print $NR}'

will display file name. But I need only path
Last edited by Scott; 11-14-2013 at 05:51 PM.. Reason: Please use code tags; and if you must use a useless subject title, please at least spell it correctly ;-)
# 2  
Old 11-14-2013
by example through bash/korn shell remove right most syntax...
Code:
[josephgr@oc0887178221 ~]$ x="/foo/bar/file.txt"
[josephgr@oc0887178221 ~]$ echo ${x%/*}
/foo/bar

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