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How to compare decimal values in bash?

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# 1  
Old 11-14-2013
How to compare decimal values in bash?
Hi,

I am facing some error while doing the comparision between 2 decimal values in bash. Pl help me out.

I have tried using below scripts. But its giving me error.

1)
Code:
amt=12.3 opn_amt=12.5 var=$(awk 'BEGIN{ print "'$amt'"<"'$opn_amt'" }')    

if [ "$var" -eq 1 ];then   echo "correct" else   echo "Wrong" fi

2)Tried using bc also as follows , but no resolution.

Code:
amt="12.3" opn_amt="12.2" if [ $(bc <<< "$amt <= $opn_amt") -eq 1 ]     then  
 echo "correct" else   echo "Wrong" fi

Thanks
Sibadatta

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Last edited by Scrutinizer; 11-14-2013 at 02:02 AM.. Reason: code tags
# 2  
Old 11-14-2013
A number of semicolons were missing, try:
Code:
amt="12.3" opn_amt="12.4"; if [ $(bc <<< "$amt <= $opn_amt") -eq 1 ]; then echo "correct"; else echo "Wrong" ; fi

You can avoid this and improve readability by using more lines:
Code:
amt="12.3" opn_amt="12.2"
if [ $(bc <<< "$amt <= $opn_amt") -eq 1 ]; then
  echo "correct"
else
  echo "Wrong" 
fi

# 3  
Old 11-14-2013
Just another way

Code:
if [  $(echo $amt - $opn_amt | bc | grep ^-) ]; then
  echo "correct"
else
  echo "Wrong" 
fi

# 4  
Old 11-14-2013
It should be noted that all of these examples are using the external bc utility, because BASH itself -- and most bourne shells except ksh -- do not support floating-point numbers.
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