Shell Programming and Scripting

Hello to all,

I'm new to perl, I have input file that contains the string below:

Code:

315350535ff450000014534130101ff4500ff45453779ff450ff45545f01ff45ff453245341ff4500000545000

This string has as line separator "ff45". So, I want to print each line but the code below is not working.

Code:

perl -pe '
local $/;
$/ = "ff45";
while (<FILE>){
    print;
}' file

If the only condition is set as line separator "ff45", the output would be:

Code:

315350535ff45
0000014534130101ff45
00ff45
453779ff45
0ff45
545f01ff45
ff45
3245341ff45
00000545000

But when the line length is less than 7 I want to concatenate that small line with the next one,
So, the final output I'd like to get is below (red part is small line, in blue next line):

Code:

315350535ff45
0000014534130101ff45
00ff45453779ff45
0ff45545f01ff45
ff453245341ff45
00000545000

May you help me in how to get this.

PS: If possible, I'd like only to modify the code inside the while loop, since I want to incorporate as part of a bigger script.

Thanks in advance.

Try this (with some assumptions):

Code:

perl -pe 'BEGIN{$/="ff45"}
$\ = (length >= 7 ? "\n" : "")' file

Hello elixir_sinari,

Thanks for the help. It works just fine!

Regards