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Fetching values in CSV file based on column name

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# 1  
Old 11-07-2013
Fetching values in CSV file based on column name

abc   ,123   ,xyz   ,000   ,pqr
mno   ,123   ,dfr   ,111   ,bbb

123   ,000
123   ,111

how to fetch the values of Field4 where Field2='123'

I don't want to fetch the values based on column position. Instead want to fetch the values based on field names(header name)

Last edited by Franklin52; 11-07-2013 at 08:19 AM.. Reason: Please use code tags
# 2  
Old 11-07-2013

$ awk -F, 'NR==1 || $2==123{print $2,$4}' OFS="," file

# 3  
Old 11-07-2013
Thanks for the reply Ajay.

But here I don't fetch values based on column position ($2==123). Instead i want to fetch value by the header name .
# 4  
Old 11-07-2013
Try by the way myself Akshay not Ajay Smilie

$ cat Header_list.txt

$ cat file
abc ,123 ,xyz ,000 ,pqr
mno ,123 ,dfr ,111 ,bbb

awk 'NR==FNR{
                Cols=Cols (Cols?"|":"")$1

                for (i=1;i<=NF;i++) 
                if (match($i,Cols)) 

               for (i=1;i<=n;i++) 
               printf (i<n)? $(Ar[i])  FS : $(Ar[i])
               printf "\n"
            }' FS=","  Header_list.txt file

Field2 ,Field4, Field4 
123,  000,  pqr 
123,  111,  bbb

# 5  
Old 11-07-2013
Or else , Is there a way to find the position of a particular field .
For example say Field 3,its in 3rd position. How to pragmatically fetch the position of field3.
# 6  
Old 11-07-2013

Did you try #4 ?
# 7  
Old 11-07-2013
Something like:
awk '
NR==1 {
   for (i=1;i<=NF;i++) {
      if ($i==SEARCHHDR) {
      if ($i==OUTHDR) {

   print $srchfld OFS $outfld

NR>1 && $srchfld ~ SEARCHVAL {
   print $srchfld OFS $outfld
' SEARCHHDR="Field2" SEARCHVAL="123" OUTHDR="Field4" FS=, OFS=, file

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