Shell Programming and Scripting

Hi,

I want to grep multiple patterns from multiple files and save to multiple outputs. As of now its outputting all to the same file when I use this command.

Input : 108 files to check for 390 patterns to check for. output I need to 108 files with the searched patterns.

Xargs -I {} grep *.txt < patterns.txt >output.txt

I want to have 108 output files for the 108 input files with the 390 search pattern. How can I acheive it?

Thanks,

I guess/hope you have

Code:

xargs -I {} grep {} *.txt <otherdir/patterns.txt >otherdir/output.txt

otherwise your search in *.txt includes patterns.txt and output.txt - with random results.
The following grep -f patternfileis easier and avoids duplicates (in case multiple patterns match)

Code:

grep -f otherdir/patterns.txt *.txt > otherdir/output.txt

For separate output files have a loop:

Code:

for file in *.txt
do
  grep -f otherdir/patterns.txt "$file" > otherdir/output."$file"
done

Thanks,

But grep -f is pulling the whole file out and writing to output instead of just the matching one's. So I used the xargs. but xargs does not give me any output. Below is the code that I used.

Code:

for file in *.count.txt
do
  xargs -I {} grep  "$file" < strings.txt > output."$file"
done

Can you explain?
In the loop grep -f prints exactly the same matching patterns (or less if there are duplicate output lines).
--
And why don't you have {} after the grep?