Shell Programming and Scripting

Same error as before...

Code:

-ksh: line 1: syntax error: `;' unexpected
$(echo -n "`logname`@`hostname`:";if [[ "${PWD#$HOME}" 1002 "$PWD" ]] then; echo -n "~${PWD#$HOME}"; else; echo -n "$PWD";fi;echo;echo "$ ")

But this now ONLY fails on hosts with Version M 1993-12-28

It works on the hosts with Version AJM 93t+ 2010-06-21.

Try the following:

Code:

PS1='$(printf "%s@%s:" "$(logname)" "$(hostname)";[ "${PWD#$HOME}" == "$PWD" ] || printf "~";printf "%s\n$ " "${PWD#$HOME}")'

Note that I reversed some of the logic so I could use "==" instead of "!=". I use set -o vi, but I have heard of some cases where set -o emacs sometimes invokes the command history mechanism when != is used. If that is part of your problem (i.e. the 1002 in red above), this change should avoid it. I used printf instead of echo -n because it is more portable. (Using echo -n abc in ksh on a Solaris system (and some other UNIX branded systems) should print -n abc followed by a newline rather than abc without a newline that you would get with ksh on some other systems.

Beautiful! Thank you... that worked perfectly on every host that failed earlier.
And thanks again for the useful tips. Much appreciated!

After closer inspection your command line does have unwanted/missing semicolons (shown in red above) so try the one below...

Code:

PS1=$(print -n "`logname`@`hostname`:";if [[ "${PWD#$HOME}" != "$PWD" ]]; then print -n "~${PWD#$HOME}"; else print -n "$PWD";fi;print "\n$ ")

which should work on all ksh versions...