Shell Programming and Scripting

is it possible to capture the 3 digit return code of ftp commands in a local variable inside a shell script?


Code:

Code:

ftp remoteserver << EOFTP 
    quote USER uid
    quote PASS pass
    prompt
    cd remote_directory
    mput file.txt
    bye
EOFTP

in the above script, if cd command returns 550 in case of failure and 226 in case of success. same way mput also returns.. how cn i capture these return codes.

Did you try to redirect stderr?

I have done that.. Using

Code:

ftp -iv remoteserver<<EOFTP> ftp.log 2>&1
    prompt
    cd remote directory
    mget file*.txt
    ls -ltr
    bye
EOFTP

After executing the above ftp.. Log file contains many replies from ftp.. For example… mget and ls -ltr both the command gives 226 as a reply for success..How can I know which reply is for which command.. N also the text after the reply codes are server dependent.

You could always insert your own trace information to help out.

You could add a pwd or dir for the remote server to process.
You could add a local command with a ! to put in a marker.

Have a go with this:-

Code:

ftp -inv remoteserver<<EOFTP> ftp.log 2>&1
    user $userid $password
    prompt
    pwd
    cd remote directory
    pwd
    dir
    !echo "`date` Get files"
    dir file*.txt
    mget file*.txt
    !echo "`date` Got files"
    bye
EOFTP

Hopefully with these you can work out where the problem is. If you need to know as the process progresses, then you may have to connect several times, so you may have a first connection to prove that you can get to the directory, a second to list the files. You might then choose to get each file in a loop so if there are any failures, you know which one you are working on.


See if that helps, but if not let us know what else would be useful and I/we will see what can be done.


Regards,
Robin

man ftp: