Resolving a parameter which is passed as parameter


 
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# 1  
Old 10-05-2013
Hammer & Screwdriver Resolving a parameter which is passed as parameter

Hi,
I have the following files.
->cat scr.sh
Code:
export TMP_DIR=/home/user/folder1
export TMP_DIR_2=/home/user/folder2
while read line
do
cat "$line"
done<file_list.dat

------------------------
-> cat file_list.dat
Code:
$TMP_DIR/file1.txt
$TMP_DIR_2/file2.txt

---------------------------
-> cat /home/user/folder1/file1.txt
Code:
This is data from file1

---------------------------
-> cat /home/user/folder2/file2.txt
Code:
This is data from file2

-------------------------------
**************************************************
In the above code when I execute the scr.sh file, variable $TMP_DIR and $TMP_DIR_2 are not getting resolved. instead the error it shows file not available:$TMP_DIR/file1.txt .
My objective is to get the content of file1 and file2 inside scr.sh for further processing.
Could someone please help me on this.

Thanks in advance
TSB

Last edited by radoulov; 10-05-2013 at 08:37 AM..
# 2  
Old 10-05-2013
You can force the shell to re-evaluate a string using eval, e.g.:
Code:
cat $(eval echo $line)

This User Gave Thanks to CarloM For This Post:
# 3  
Old 10-05-2013
Thanks a lot.
This worked.
# 4  
Old 10-05-2013
Please be aware that eval is deprecated and dangerous.

Nevertheless, you can simplify above to
Code:
eval cat "$line"

# 5  
Old 10-07-2013
Hi,

When I use
Code:
eval cat "$line"
or
cat $(eval echo $line)

and my filename contains spaces - I get the following error - " No such file or directory"



For Ex:

-> cat filelist.dat
Code:
$TMP_DIR/file f1.txt

It throws the following:
Code:
cat: /home/user/folder1/file: No such file or directory
cat: f1.dat: No such file or directory

Where as when I use cat "file f1.txt" it works, though without $TMP_DIR. But my objective is to attain $TMP_DIR resolution and file expansion.

Can you plz help on this?


Thanks in advance
TSB

Last edited by radoulov; 10-07-2013 at 11:28 AM..
# 6  
Old 10-07-2013
As you've noted, you need to quote the string to supply a pathname containing spaces. The same still applies when you're using a variable.

Code:
cat "$(eval echo \"$line\")"

Technically, the extra quotes around $line aren't necessary for your example case but if you want to preserve other whitespace then you will need them (without them echo will receive 2 arguments, which it will print with a space separator),
This User Gave Thanks to CarloM For This Post:
# 7  
Old 10-07-2013
Code:
eval cat \"$line\"

This User Gave Thanks to RudiC For This Post:
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