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awk - grep particular word from output

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# 1  
Old 10-03-2013
awk - grep particular word from output
Hi Experts,

- Getting error while using it through a variable to get the PID,

Code:
PID=42
# UNIX95=1 ps -e -o pcpu,pid,ppid,stime,etime,args | awk '{if ($2~"^42$") print $0}'
 0.00    42     0  Feb 10  600-17:21:29 nfs_async_io




- But when using with a variable it is not working .
Code:
# UNIX95=1 ps -e -o pcpu,pid,ppid,stime,etime,args | awk -v pid1=$PID '{if ($2~^pid1$) print $0}'
 syntax error The source line is 1.
 The error context is
                {if >>>  ($2~^ <<< pid1$) print $0}
 awk: The statement cannot be correctly parsed.
 The source line is 1.




please advise what is wrong happening..
Last edited by joeyg; 10-03-2013 at 03:58 PM.. Reason: moved code tags, changed "lime" to "green"
# 2  
Old 10-03-2013
Try ($2==pid1)

EDIT: Or, maybe, ($2 ~ "^"pid1"$") ?
This User Gave Thanks to RudiC For This Post:
rveri
# 3  
Old 10-03-2013
Try

Code:
"^"pid1"$"

I suppose there is a good reason to do this but, why not just use the the switich to specify the specific pid...so something like

Code:
ps -T ${PID}

and the -o options you are interested in.
# 4  
Old 10-03-2013
Hi blackrageous,

It did not work ,

Code:
PID=42
$ ps -T ${PID}
ps: illegal option -- T
usage: ps [-edaxzflP] [-u ulist] [-g glist] [-p plist] [-t tlist] [-R prmgroup] [-Z psetidlist]
$

This is ksh on hp-ux 11.23. Please advise,
Thanks,
# 5  
Old 10-03-2013
It's -p for proc list (which I assume was the aim).
This User Gave Thanks to CarloM For This Post:
rveri
# 6  
Old 10-03-2013
Try:
Code:
UNIX95=1 ps -p "$PID" -o pcpu,pid,ppid,stime,etime,args

-edit- OK, I see CarloM already answered this one..
This User Gave Thanks to Scrutinizer For This Post:
rveri
# 7  
Old 10-03-2013
RudiC thanks, worked the first one.
CarolM & Scrutinizer, thanks worked too... ,
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