How to suppress error in following command?


 
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# 15  
Old 10-02-2013
Not sure I understand correctly, but try (untested):
Code:
awk -F"\t" '/^040/      {REC1++; SUM1+=$15; FN=FILENAME}
            /^600/      {REC2++; SUM2+=$18; FN=FILENAME}
            END         {printf ("%s;%d;%0.2f;%d;%0.2f\n", FN,REC1,SUM1/100, REC2,SUM2/100)}
           ' myfile.txt

# 16  
Old 10-17-2013
Hi RudiC,

Thank you for your reply. Yes you got it correct and I will arrange it accordingly as per my requirement. But this command fails to print the file name in case there is no row starting with either 040 or 060. In such scenario the output is coming as below:

Code:
0;0.00;

How do I print the file name as below when there is no record starting with 040 or 060:
Code:
0;0.00;myfile.txt

Thanks
Angshuman
# 17  
Old 10-17-2013
Put the {FN=FILENAME} on its own single line upfront. (You can then remove it from the two other lines).
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