How to suppress error in following command?

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# 8  
Old 09-30-2013
You may want to set the OFMT (output format; default "6.2f") variable to a more suitable value.
If you try MadeInGermany's proposal, use printf, not print.

EDIT: wrong default from the top of my head. Correct: "%.6g"

Last edited by RudiC; 09-30-2013 at 03:18 PM..
This User Gave Thanks to RudiC For This Post:
# 9  
Old 10-01-2013
Hi All,

Thank you all for your valuable input. Yes I managed to print the number correctly using the printf function. However, I got another issue with the command provided by RudiC.

I am applying the same command on another file in which record separator is not pipe. I change the command as below:

awk -F" " '/^040/ {REC++; SUM+=$14; FN=FILENAME} END {printf ("%s;%d;%0.2f\n", FN,REC,SUM/100)} ' $FILENAMEA

Using above I do not get the correct result. This is because field 14 is not being grepped correctly.

I tried following command also:

awk '{$1=$1}1' OFS="|" $FILENAMEA | awk -F" " '/^040/ {REC++; SUM+=$14; FN=FILENAME} END {printf ("%s;%d;%0.2f\n", FN,REC,SUM/100)} '

However, this did not work as filename is not being printed and the sum is also coming wrong.

Please advise.

# 10  
Old 10-01-2013
Please post input files.
# 11  
Old 10-01-2013
Hi RudiC,

Please find the attached file.

# 12  
Old 10-01-2013
What's wrong - $14 is 0 in both lines starting with 040, so the sum is 0 as well.
# 13  
Old 10-01-2013
Hi RudiC,

I am not sure with previous file. However, please refer to this attached file.

When I run both the following commands, I get two diff output.

awk -F" " '/^040/ {REC++; SUM+=$15; FN=FILENAME} END {printf ("%s;%d;%0.2f\n", FN,REC,SUM/100)} ' myfile.txt

output : myfile.txt;2;0.00

grep ^040 myfile.txt | cut -f14



These files are tab delimited. If you notice, you will see that some of the fields have text separated by space. Hence If I use space as delimiter, the output will not be consistent. When I use cut command to get field 14, I get consistent result across all files.

For example in the following line

040     40      0       0123683106      00389486375     80      RCCCFN  11      1380302611      02      03      MOBILE 012      0       40      0       NL02

MOBILE 012 is one field. If you check the second file that I have uploaded, you can see that this particular field can have text containing multiple spaces.


Last edited by angshuman; 10-01-2013 at 09:29 PM..
# 14  
Old 10-02-2013
Hi RudiC,

I managed to get that working. As I said the delimiter is tab and hence I have changed the delimiter as below:

awk -F" " '/^040/.....  is changed to awk -F'\t'  '/^040/....

After that it is working fine. However, I got another question here.

Besides lines starting with 040, if I have to grep another line starting with say 600 and sum 18th column of that line but all the output should display in one line, do I need to perform it separately and then paste the output or is there anything that can be changed in the command above to get the required output.


Last edited by angshuman; 10-02-2013 at 02:23 AM.. Reason: clarification
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