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Using variable within awk


 
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# 8  
Old 09-18-2013
As a side note:

1. Some old awk implementations don't support the -v var... syntax:
Code:
bash-3.00$ awk -v x=1 '{ print x }' <<< a
awk: syntax error near line 1
awk: bailing out near line 1
bash-3.00$ awk '{ print x }' x=1  <<< a
1
bash-3.00$ type awk; uname -sr
awk is hashed (/usr/bin/awk)
SunOS 5.10

You should use either nawk or the X/Open version of awk (/usr/xpg4/bin/awk) on Solaris anyway.

2. When you're using the syntax below, the value(s) is/are not available in the BEGIN block:
Code:
bash-3.00$ awk 'BEGIN { print x }' x=1 <<< a

bash-3.00$ /usr/xpg4/bin/awk 'BEGIN { print x }' x=1

bash-3.00$ nawk 'BEGIN { print x }' x=1

bash-3.00$

# 9  
Old 09-18-2013
@Corona688: I do not disagree, I only correct the error of the single quote on the syntax of the example.
But, it is true that I have also fixed the method.Smilie

Regards.
This User Gave Thanks to disedorgue For This Post:

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