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How To Perform Mathematical Operation Within If in awk?


 
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# 1  
Old 09-17-2013
How To Perform Mathematical Operation Within If in awk?

Hi All,

I am using an awk script as below:

Code:
awk -F'|' 'BEGIN{OFS="|";} { if ($1==$3 && $3==$7 && $7==$13 && $2==$6 && $6==$11 && $15-$14+1==$11) print $0"|""TRUE"; else print $0"|""FALSE"; }' tempfile.txt

In above script, all conditions are being checked except the one which is underlined. Can any one please help me to identify the error?

Thanks
Angshuman
# 2  
Old 09-17-2013
Try enclosing that part in brackets:
Code:
... && ($15-$14+1==$11)) ...

# 3  
Old 09-17-2013
The order of operations in that is ambiguous. Parenthesize defensively.

Code:
( ($15-$14)+1==$11 )

# 4  
Old 09-17-2013
Quote:
Originally Posted by Corona688
The order of operations in that is ambiguous. Parenthesize defensively.

Code:
( ($15-$14)+1==$11 )

According to the standards, in awk all of the following are required to produce identical results:
Code:
if ($6==$11 && $15-$14+1==$11)
if (($6==$11) && ($15-$14+1==$11))
if (($6==$11) && (($15-$14+1)==$11))
if (($6==$11) && ((($15-$14)+1)==$11))


angshuman,
What was the input line and what field separator were you using when $15-$14+1==$11 did not give you the results you expected; or if you changed the value of $11, $14, or $15 after reading the line, what values did they have when $15-$14+1==$11 gave you unexpected results?
# 5  
Old 09-17-2013
Quote:
Originally Posted by Corona688
The order of operations in that is ambiguous. Parenthesize defensively.

Code:
( ($15-$14)+1==$11 )

Corona688,

+ and - are associative, so I don't know how there could be any ambiguity.

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