How to print in the new line?


 
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Top Forums Shell Programming and Scripting How to print in the new line?
# 8  
Old 09-13-2013
Quote:
Originally Posted by apmcd47
It works for ksh93 on Linux for me. Try putting the prints back in instead of the echos. What system are you running this on?

Andrew
I am on AIX 5.3 having Korn shell.

Furthermore, if you have noticed my original script contains "print" command only.

Plz advise !
# 9  
Old 09-13-2013
Quote:
Originally Posted by targetshell
I am on AIX 5.3 having Korn shell.

Furthermore, if you have noticed my original script contains "print" command only.

Plz advise !
As I said before try replacing my echo commands with print commands:
Code:
{
   read x
   y=$x
   i=1
   while [ $i -le $x ]
   do
      j=1
      while [ $j -le $y ]
      do
            print -n $j
         j=`expr $j + 1`
      done
      print
      i=`expr $i + 1`
      y=`expr $y - 1`
   done
}

Andrew
# 10  
Old 09-13-2013
Quote:
Originally Posted by apmcd47
As I said before try replacing my echo commands with print commands:
Code:
{
   read x
   y=$x
   i=1
   while [ $i -le $x ]
   do
      j=1
      while [ $j -le $y ]
      do
            print -n $j
         j=`expr $j + 1`
      done
      print
      i=`expr $i + 1`
      y=`expr $y - 1`
   done
}

Andrew
Thanks it worked !!

Can you explain the changes in the scripts and justifications of the same.
# 11  
Old 09-13-2013
Quote:
Originally Posted by targetshell
Thanks it worked !!

Can you explain the changes in the scripts and justifications of the same.
I simply used echo because I normally use bash, and print does not exist in bash. Indentation was put in to aid readability. The only real change was the print after the inner loop, to break the line where required.

Andrew
# 12  
Old 09-13-2013
Quote:
Originally Posted by apmcd47
I simply used echo because I normally use bash, and print does not exist in bash. Indentation was put in to aid readability. The only real change was the print after the inner loop, to break the line where required.

Andrew

Hi Andrew,

I have the same question as in what is the purpose of the "Second print" that you used in the script.

Rgds,
# 13  
Old 09-13-2013
Quote:
Originally Posted by targetshell
Hi Andrew,

I have the same question as in what is the purpose of the "Second print" that you used in the script.

Rgds,
Basically you wanted
Code:
1234
123
12
1

but were getting
Code:
1234123121

The inner loop was printing
Code:
1234

the first time followed by the shorter strings each iteration. You did this by forcing print to not print the newline character at the end of each print operation. At some point, though, you wanted a newline character to start the next iteration on a new line.

Andrew
# 14  
Old 09-13-2013
Try also (feeling guilty about using the deprecated and dangeraous eval)
Code:
read ST
5
for i in $(eval echo {$ST..1}); do eval echo {$i..1}; done
5 4 3 2 1
4 3 2 1
3 2 1
2 1
1

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