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How to insert an array element within regex?

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# 1  
Old 09-09-2013
How to insert an array element within regex?

Hello to all,

I'm trying to separate the string "str" using a regex within match function.

The substrings that I want to separate, begin with 22, 23, 24 or 25 and followed by 12 or 14 characters. And I want to
replace 22 with MJS, 23 with UYT, 24 with WER and 25 with PIL.

For this string "str", the substrings I want to match are:

The code I've got so far it works if I write one regex for each substring like this:
if ( match(str, /22(.{10})(.{2})/, t) )
if ( match(str, /23(.{10})(.{2})/, t) )
if ( match(str, /24(.{10})(.{2})(.{2})/, t) )
if ( match(str, /25(.{10})(.{2})/, t) )

But I'm trying to include a "for loop" for each element of array "m[i]" but I don't know how to do it or a better way to do it.

awk 'BEGIN {


if ( match(str, /m[i](.{10})(.{2})(.{2})?/, t) )
	printf("%s,%s,%s ",p[i],t[1],t[2],t[3]);

the desired output is:
MJS,0300460754,51 UYT,0200460754,51,69 PIL,0900460754,51

PS: I want to do it in awk, because the string "str" is get inside a major awk script.

Thanks in advance for any help.

Last edited by Ophiuchus; 09-10-2013 at 12:04 AM..
# 2  
Old 09-10-2013
Try this,
echo "22030046075451230200460754516925090046075451" | awk -F "2[2345]" 'BEGIN{p[22]="MJS,"
{a=substr($0,1,2); printf p[a];for (i=2;i<=NF;i++) {
len=length($i);lntotal+=len+2; if (len >= 12 ) { printf substr($i,1,10)","substr($i,11,2);} if (len == 14 ){ printf ","substr($i,13);} b=substr($0,lntotal+1,2);if(p[b]) { printf ", "p[b]};
} printf "\n";

# 3  
Old 09-10-2013

Create a variable with the regular expression characters, then use that variable in the match function.

Best wishes ... cheers, drl

Last edited by drl; 09-10-2013 at 04:21 PM..
# 4  
Old 09-10-2013
Hello pravin27,

Thank you for the help, the issue is that the main awk program has another field separator
and I couldn't include this new FS without affect the rest.

Hello drl,

I've tried put all characters of the regex in a variable but doesn't work, only works when
I write literally the regex within match function.

Thanks for any help.
# 5  
Old 09-10-2013

Here's an example:
#!/usr/bin/env bash

# @(#) s2	Demonstrate awk built-in function match(target,re-string).

# Utility functions: print-as-echo, print-line-with-visual-space, debug.
# export PATH="/usr/local/bin:/usr/bin:/bin"
pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C awk


pl " Input data file $FILE:"
cat $FILE

pl " Results:"
awk --posix '
	BEGIN { re = "ab{2}" }
	{ if ( match($0,re) ) { print " Matched",re,"in",$0; next} }
	{ print " NO match for",re,"in",$0}

exit 0

$ ./s2

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian GNU/Linux 5.0.8 (lenny) 
bash GNU bash 3.2.39
awk GNU Awk 3.1.5

 Input data file data2:

 NO match for ab{2} in a
 NO match for ab{2} in ab
 Matched ab{2} in abb
 NO match for ab{2} in aab
 Matched ab{2} in aabbbb

Note that for some special characters in REs, one must use --posix with gawk.

Best wishes ... cheers, drl

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