2 dollars wrapped to a string

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# 1  
Old 09-02-2013
2 dollars wrapped to a string


I am writing an awk script and I have got stuck. I am trying to find a word that has 2 dollar signs in it but its failing. I have already tried to escape it with single and double back slash and also I have tried to use \044 in the search but even that doesnt work. can you please help me with the pattern?

input: Hello world $string$
Expected output: string

I have already tried below patterns

echo "Hello world $string$" | awk '/\$.*\$/ { print "match found" }'
echo "Hello world $string$" | awk '/\\$.*\\$/ { print "match found" }'
echo "Hello world $string$" | awk '/\$\$/ { print "match found" }'
echo "Hello world $string$" | awk '/\\$\\$/ { print "match found" }'
echo "Hello world $string$" | awk '/\044.*\044/ { print "match found" }'

Last edited by Scott; 09-02-2013 at 05:22 AM.. Reason: Quote tags -> Code tags
# 2  
Old 09-02-2013

Could you please try the following code.

echo "Hello world "$"string"$"" | awk -F" " '{print$3}'

Output will be as follows.

kindly let me know if you have any queries.

R. Singh
# 3  
Old 09-02-2013
Originally Posted by hitmansilentass
I have already tried below patterns
echo "Hello world $string$" | awk '/\$.*\$/ { print "match found" }'

Use single quote with echo instead of double quotes, so that shell doesn't interpret $string as a variable.

echo 'Hello world $string$' | awk '/\$.*\$/ { print "match found" }'

# 4  
Old 09-02-2013
Use single quoting to prevent the shell from treating the $ and your test will work:
# echo 'Hello world $string$'|awk '/\$[a-z]*\$/ { print "match found" }'                         
match found

# 5  
Old 09-02-2013
To print the strings that are enclosed by $ in a file :

awk '{for (i=1;i<=NF;i++)  if($i ~ /^\$/ && $i ~ /\$$/)  {print substr($i,2,length($i)-2)} }' inputfile

Hello world $string$
def $kk$ df


# 6  
Old 09-02-2013
Two levels of escape, one for the shell and one for the RegExp. Either '\$' or '[$]'
sed -n 's/.*[$]\([^$]*\)[$].*/\1/p'

echo needs one level (for the shell), either '$' or \$

Last edited by MadeInGermany; 09-02-2013 at 05:26 AM..
# 7  
Old 09-02-2013
echo 'Hello world $string$' | awk -F\$ '{print $2}'

You need to use single quote ' not double quote ". With double quote it threat $string as a variable and tries to substitute it.
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