[Solved] 0403-057 Syntax error for if statement


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# 1  
[Solved] 0403-057 Syntax error for if statement

I am getting the following error when I am running a script in ksh when trying to execute an if statement comparing two numerical values

Code:
tstmb.sh[26]: 1.5321e+08: 0403-057 Syntax error

Below is my code snippet.

Code:
#!/bin/ksh
set -x
TODAY=$(date +%y%m%d)

for file in $(ls -rt  *.log | tail -1)
do

V=$file
V1=${V#*_}
V2=${V1%%_*}

if [ "$V2" -ne "$TODAY" ];
then

echo "abc"

elif <condition>
then
echo "xyz"
else
echo "123"

fi
done

Code:
TODAY=130830
+ V=ABC_130830_001.log
+ V1=130830_000004.log
+ V2=130830
+ [ 130830 != 130830 ]
test.sh[12]: 1.5321e+08: 0403-057 Syntax error

Please let me know where I am doing wrong..Thanks,
# 2  
Quote:
an if statement comparing two numerical values
"$V2" the way its written is a string and quite sure $TODAY also...
# 3  
What I meant was comparing two numbers:

ie., 130830 != 130830

This does not seem to work and so does using '-ne'
any idea why Smilie
# 4  
because -ne is for numeric and what your declared are chars...
Where did you declare as numeric?
# 5  
Your test:
Code:
if [ "$V2" -ne "$TODAY" ];

is comparing strings (because your variables ar in quotes) using a numeric (-eq) operator.

It should be:
Code:
if [ $V2 -ne $TODAY ];

# 6  
You are not showing us the correct output from your script... or not showing the correct script:
Code:
+ [ 130830 != 130830 ]
test.sh[12]: 1.5321e+08: 0403-057 Syntax error

Does not match...!!!
What have you hidden?
# 7  
Quote:
Originally Posted by port43
Your test:
Code:
if [ "$V2" -ne "$TODAY" ];

is comparing strings (because your variables ar in quotes) using a numeric (-eq) operator.

It should be:
Code:
if [ $V2 -ne $TODAY ];

That makes no difference, really. A number is a number by virtue of containing numerals whether it is quoted, or not. And if the two numbers are equal as strings it doesn't matter if you use != or -ne.

Last edited by Scott; 08-30-2013 at 12:57 PM.. Reason: Reword
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