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Schedule Job Fortnightly (FRI) in Crontab


 
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# 1  
Schedule Job Fortnightly (FRI) in Crontab

Solaris platform.
How can I schedule crontab job every 2 weeks and the job to be scheduled on Fri?
# 2  
https://www.unix.com/unix-advanced-ex...ther-week.html

Code:
# "first" friday  -- and note # generally does work in crontab files as a comment
0 8 ** 6  [ $((  $(( $(date +%s ) / 86400  )) % 2 )) -eq 0 ] && /path/to/myjob
#  "second" friday
0 8 ** 6  [ $((  $(( $(date +%s ) / 86400  )) % 2 )) -eq 1 ] && /path/to/myjob

# 3  
No Solaris platform available to test but this crontab entry :

Code:
0 10 * * 5 [ $(( $(date +'\%U') % 2)) -gt 0 ] && /usr/local/bin/your_script

Or run your script every friday and test week of year is odd with

Code:
if [ $(( $(date +%U) % 2 )) -gt 0 ]

Note: % has special meaning to many versions of cron and usually needed to be quoted

Last edited by Chubler_XL; 08-28-2013 at 10:27 PM.. Reason: Note about % in crontab
These 2 Users Gave Thanks to Chubler_XL For This Post:
# 4  
FWIW- % on a crontab line is POSIX for "end of line". Any lines after the % character are considered stdin
# 5  
Hi All,

Thanks for the reply.
I'd tried as below, but encountered error.

0 8 ** 6 [ $(( $(( $(date +%s ) / 86400 )) % 2 )) -eq 0 ] && $HOME/admin/scripts/rjob.sh
crontab: error on previous line; unexpected character found in line.
crontab: errors detected in input, no crontab file generated.

---------- Post updated at 08:51 AM ---------- Previous update was at 08:41 AM ----------

I'm able to schedule with below syntax. Shall feedback the result..
0 10 * * 5 [ $(( $(date +'\%U') % 2)) -gt 0 ] && /usr/local/bin/your_script

---------- Post updated at 09:00 AM ---------- Previous update was at 08:51 AM ----------

[QUOTE=Chubler_XL;302848241]No Solaris platform available to test but this crontab entry :

Code:
0 10 * * 5 [ $(( $(date +'\%U') % 2)) -gt 0 ] && /usr/local/bin/your_script

Or run your script every friday and test week of year is odd with

Code:
if [ $(( $(date +%U) % 2 )) -gt 0 ]


Tested using below:
at now [ $(( $(date +'\%U') % 2)) -gt 0 ] && /path/rjob.sh
ksh: \35 % 2: syntax error
# 6  
Quote:
Originally Posted by KhawHL

... ... ...

Quote:
Originally Posted by Chubler_XL
No Solaris platform available to test but this crontab entry :

Code:
0 10 * * 5 [ $(( $(date +'\%U') % 2)) -gt 0 ] && /usr/local/bin/your_script

Or run your script every friday and test week of year is odd with

Code:
if [ $(( $(date +%U) % 2 )) -gt 0 ]


Tested using below:
at now [ $(( $(date +'\%U') % 2)) -gt 0 ] && /path/rjob.sh
ksh: \35 % 2: syntax error
You're making it too hard on yourself, just use:
Code:
if [ $(( $(date +%U) % 2 )) -gt 0 ]
then    /path/rjob.sh
fi


Last edited by Don Cragun; 09-03-2013 at 10:18 PM.. Reason: Fix mismatched QUOTE tags
# 7  
Also at now is not a valid way to test crontab entries particularly these ones with escaped percent symbols.

You are better off just writing a script that updates/appends to a logfile and scheduling it for 5 or 10 mins in the future and waiting for cron to run it.

eg if the current time was:

Tue, Sep 03 4:25 PM

Schedule a test for 4:30 PM :

Code:
30 16 * * *  [ $(( $(date +'\%U') % 2)) -gt 0 ] && echo "Script run" >> /tmp/test.log

Wait 5 mins and check /tmp/test.log

Last edited by Chubler_XL; 09-03-2013 at 10:37 PM..

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