Shell script to replace output of command


 
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# 1  
Old 08-26-2013
Shell script to replace output of command

Hi

I would like to write a shell script which replace particular text in output of a shell command. For example : If I execute pwd (if dir is /users/master/) it should display as - /users/Master_directory/.

Also, for generalising the script I would like to receive parameters when I run the shell script.

Help will be appreciated.

Thanks
Ratnesh
# 2  
Old 08-26-2013
Post how you want to run the script..do you want something like this ?

Code:
bash# ./replace.sh "pwd" "master" "Master_directory"

# 3  
Old 08-26-2013
Quote:
Originally Posted by rajamadhavan
Post how you want to run the script..do you want something like this ?

Code:
bash# ./replace.sh "pwd" "master" "Master_directory"


Below is rough outline :

1. Call script with few parameters like " -firstparam One -secondparam Two"
2. In script execute a unix command lets say "cat example.txt". Original output is -
This is line number 1
This is line number 2

3. Replace data in output -
1 is replaced by One and 2 by Two

4. Displays final output -
This is line number One
This is line number Two

I hope I am clear enough
# 4  
Old 08-26-2013
And what have you done so far?
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