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[Solved] Output on one line


 
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Top Forums Shell Programming and Scripting [Solved] Output on one line
# 1  
Old 08-19-2013
[Solved] Output on one line

A simple question, but i am finding it diffcult to find the answer.

Can you please tell me how i can get the output of two line on one.

I am aware i need to enter \ something, but no sure which charcter, can you advice.


CODE

Code:
for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `
        do
        echo "$i" ; bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} ' | awk 'NR==1{print $1,$2,$5,$10,$11}'

Output currerntly
Code:
algomd01
08/16/2013 20:23 1577925 LDN_WAT_UX_DEV
allocd01
allocp01
08/18/2013 23:50 2575795 LDN_CAM_UX_PRD
apmapp01


Output required
Code:
algomd01    08/16/2013 20:23 1577925 LDN_WAT_UX_DEV
allocd01
allocp01      08/18/2013 23:50 2575795 LDN_CAM_UX_PRD
apmapp01

# 2  
Old 08-19-2013
For awk i think you can use
Code:
printf ("%s", $0)

instead of
Code:
print $0

Hope it helps.
# 3  
Old 08-19-2013
Try this

Code:
for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `        do        echo "$i `bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} ' | awk 'NR==1{print $1,$2,$5,$10,$11}'`"

# 4  
Old 08-19-2013
Sorry did not work... Same output as before capitanui and prasperl

Last edited by Junes; 08-19-2013 at 08:56 AM..
# 5  
Old 08-19-2013
Please try the below given code in your shell..just to want to see the outcome

Code:
echo "I am `whoami`!"

# 6  
Old 08-19-2013
# echo "I am `whoami`!"
I am root!

---------- Post updated at 01:00 PM ---------- Previous update was at 12:57 PM ----------

adsdbi01.zit.commerzbank.com\c
algomd01.zit.commerzbank.com\c
08/16/2013 20:23 1577925 LDN_WAT_UX_DEV
# 7  
Old 08-19-2013
Thats good..My suggestion was also on the same logic...I guess your "$i" itself has a \n
...My suggestions
Code:
for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `
        do
        echo -n "$i"
echo  "`bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} '`"

Or

Code:
for i in `cat LDN_HOSTS_190813 | grep -i LDN | awk '{print $1}' | sort -u `
        do
        var1=`echo "$i" | tr -d '\n'`
var2=`bpimagelist -client $i -d 08/14/2013 18:00:00 -U | egrep -vi "Expires|-" | awk '  { if($5 > 1000000) print $0} '`"
echo "$var1 $var2"


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