Shell Programming and Scripting

Hi

I have a requirement to check whether the files exists, then it will call other steps in shell script.

I did

Code:

ls *.csv|wc -l
if [ -f *.csv ]

then checking the count of the files should be more than 1 then it will call other steps.

I am getting the error that too many arguements as there n number of files which has .csv.

Is there any other way we can check file existence? I don't need the count of the files, just need whether the files are there to process.

Thanks in advance

Maybe something like this:

Code:

for file in *.csv; do
  if [ -f $file ]; then
  ...
  fi
done

Thanks Bartus,

It works if i do process one by one file until there are no files.
I don't want to pick any files which arrive after my process is invoked. So I am checking whether the files exists, If exists i write all files into one one file, then i take the file name from that file and do the actual process.

The latter might work if the shell can take more arguments than ls.
Allow unlimited files:

Code:

\ls |
while read file
do
  if [ -f "$file" ]
  then
    case $file in
    *.csv) ;;
    *) continue;;
    esac
    ...    
  fi
done

I did \ls to escape an alias in interactive shells.
Some shells allow a more comprehensive match than the case statement.

My Script which i am using:

Code:

cd /var/opt/input
filecount=$(find . -type f -name *.csv | xargs wc -l)
if [ $filecount -gt 0 ]
then
echo "Number of Files are $filenumber"
else
echo "No Files"
fi

When the Input locations has huge number of files it is giving error saying

Code:

find . -type f -name "*.csv" | wc -l

This gives only a number, and can be stored in a variable as you did.
But storing the list in a variable can lead to a "too long" error in the shell.

Thanks

But i don't want to store list in variable i just need to store count value into Variable. still getting the same error.

Any other way to get this done?