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Shell Programming and Scripting

Find number of digits in a word

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# 1  
Old 08-07-2013
Find number of digits in a word
HI,

Can you tell me how to find the number of digits in a word.

Code:
 
$cat data.txt
+123456ad
87645768


Output should be
6
8
# 2  
Old 08-07-2013
Code:
awk '{for(i=1;i<=length($0);i++){if (substr($0,i,1)>=0 && substr($0,i,1)<=9) {++x}}{print x;x=0}}' data.txt

# 3  
Old 08-07-2013
Code:
awk '{n=gsub(/[0-9]/,"&");print n}' data.txt

This User Gave Thanks to Yoda For This Post:
RavinderSingh13
# 4  
Old 08-07-2013
Since lines is not printed, there is no need to use the "&"
This should work fine too.
Code:
awk '{n=gsub(/[0-9]/,x);print n}' data.txt

PS Nice idea on how to count the digit Smilie
# 5  
Old 08-08-2013
Quote:
Originally Posted by Jotne
Since lines is not printed, there is no need to use the "&"
Simplifying further, there's also no need for n:
Code:
awk '{print gsub(/[0-9]/,x)}' data.txt

Regards,
Alister
# 6  
Old 08-08-2013
This should work also:
Code:
awk '{print (NF-1)}' FS='[0-9]' data

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