Shell Programming and Scripting

Is there a way for a bash script to test if it can cd into a directory without actually attempting to cd into it?

I am looking for something along the lines of:

Code:

if [ -d $dir ];then
     #code to execute
fi

except in this case I don't want to test if the directory exists; what I want is to test if the script has the permission to cd into the directory.
I know there are other ways of achieving this but does bash provide a shortcut?

A process can "cd" into a directory when it has execute-rights on it. Test simply if it is a directory AND if the x-bit is set for you:

Code:

if [ -d "$dir" -a -x "$dir" ] ; then
     # do something here
fi

I hope this helps.

bakunin

You can also try:

Code:

if ( cd "$dir" 2>/dev/null )
then    # do something
fi

If you want the diagnostic from cd if the cd failed, drop the redirection, or if you want a custom diagnostic add an else clause to your if statement. Performing the cd in a subshell will not affect the current working directory for the rest of this script.

Some people find this form easier to understand, but creating a subshell won't be as efficient as running

Code:

test -d "$dir" && test -x "$dir"

in the current shell execution environment.

Just test $?. If it's zero, the "cd" worked.

I vote for

Code:

test -d "$dir"/.

This fosters an autofs mount or an AFS volume mount, so is as safe as an actual cd. No need for an additional test -x.

That's insufficient. If all but the final path component have execute/search permission, the stat() syscall for test -d succeeds, but the chdir() syscall for cd fails.

Regards,
Alister

ok. insightful -- doing the cd in a subshell. thanks!

---------- Post updated at 02:14 AM ---------- Previous update was at 02:13 AM ----------

exactly what i was hoping to find. thanks.