Help with Using "while" loop to output series of numbers


 
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# 1  
Old 07-24-2013
Question Help with Using "while" loop to output series of numbers

Trying to use "while" loop command to create a series of numbers that looks like the following:
0 .
1 0 .
2 1 0 .
3 2 1 0 .
4 3 2 1 0 .
5 4 3 2 1 0 .
6 5 4 3 2 1 0 .
7 6 5 4 3 2 1 0 .
8 7 6 5 4 3 2 1 0 .
9 8 7 6 5 4 3 2 1 0 .

I am very new to shell scripting and any help would be greatly appreciated.
Thanks
# 2  
Old 07-24-2013
Have you tried any pseudocode yet? If not, please try and then we can suggest the unix command to be used for each of the steps.
# 3  
Old 07-24-2013
post your code what you have tried. its simple. u can use two while loops.. try it u will get it.. if not then post the code, someone will fix it for sure..
# 4  
Old 07-24-2013
Code:
#!/bin/bash
i="0"
p="."
while [ $i -lt 10 ]
        do
        p="$i $p"
        echo $p
        ((i++))
done

This User Gave Thanks to Jotne For This Post:
# 5  
Old 07-24-2013
another way:

Code:
i=0
while [ $i -le 9 ]; do
        j=$i
        while [ $j -ge 0 ]; do
                echo -n "$j "
                (( j-- ));
        done
        echo "."
        ((i++))
done

This User Gave Thanks to Little For This Post:
# 6  
Old 07-24-2013
Just for test: awk
Code:
awk 'BEGIN {a="."; for (i=0;i<=9;i++) {a=i" "a;print a}}'

# 7  
Old 07-24-2013
Without explicit looping:
Code:
seq 0 9 | sed '1s/$/ ./; 1!G; y/\n/ /; h'

Regards,
Alister
This User Gave Thanks to alister For This Post:
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