Shell Programming and Scripting

Hi Rudi. Thank you again for the reply.
I added your suggestion, this is what the code now looks like now:

Code:

ls -R | grep -ov "[0-9][0-9][0-9][0-9][0-9][0-9][0-9]_[0-9][0-9][0-9]_[1-4]\..*$" | xargs ls > Bad_Filenames.txt

This is what I received in the Terminal window as feedback:

ls: ./lrg:: No such file or directory
ls: ./med:: No such file or directory
ls: ./sm:: No such file or directory
ls: 1234567_56_2.jpg: No such file or directory
ls: 123456_123_2.jpg: No such file or directory
ls: 9876543-654_1.jpg: No such file or directory
ls: 9876543_654-1.jpg: No such file or directory

It did output the file, but listed all of the images, not just the ones that did not follow the naming convention.

I have attached my test folder structure so all can see what I'm trying to do.
It also contains the output file that resulted.

Ok, so I changed the xargs command from:

Code:

xargs ls > Bad_Filenames.txt

to

Code:

xargs > Bad_Filenames.txt

This gives me a file with the correct output, but can I have it listed 1 item per line, as opposed to all results on a single line?

What be the output of the ls ... | grep -ov ... alone, without the pipe to xargs? I think the error msgs above are self-explanatory as the filenames without path prepended of course don't exist...