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Getting syntax error while running awk command

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# 1  
Old 07-03-2013
Getting syntax error while running awk command
Hello Gurus,

I am firing the below command :

Code:
df -g | grep -v var| awk '{ (if $4 > 90% ) print "Filesystem", $NF,"over sized";}'

But I am getting the below error:-
======
Code:
syntax error The source line is 1.
 The error context is
                {if ($4 > >>>  90%) <<<
 awk: The statement cannot be correctly parsed.
 The source line is 1.

Please suggest.

Thanks-
Pokhraj
Last edited by radoulov; 07-03-2013 at 05:56 AM..
# 2  
Old 07-03-2013
Code:
df -g | grep -v var| awk '{ if ( $4 > "90%" ) print "Filesystem", $NF,"over sized";}'

# 3  
Old 07-03-2013
Hello,


Could you please try theis following code and let me know if this helps.

Code:
 
$ df -g | grep -v "var" | awk '{sub(/\%/,"",$0)} {print$1" "$4}' | awk '{ if ( $2> "90" ) print $1 ,"over sized";}'
Filesystem over sized
/mnt over sized


Thanks,
R. Singh
# 4  
Old 07-03-2013
Thanks Anbu23 for your help.
But the command throwing some extra lines as below:-
======
Filesystem on over sized
Filesystem /febsmt/orasoft_bck over sized
Filesystem /febsdb/orasoft over sized

Why this line is coming.. Any idea.

Thank-
Pokhraj
# 5  
Old 07-03-2013
Code:
df -g | grep -v var| awk ' NR>1 { if ( $4 > "90%" ) print "Filesystem", $NF,"over sized";}'

# 6  
Old 07-03-2013
pkhraj_d,
check this out..
Code:
df -g | grep -v -e var -e Filesystem | sed 's/%/ /g'|awk '{ if ( $4 > 90 ) print "FILESYSTEM", $NF,"over sized";}'

Enjoy.
# 7  
Old 07-03-2013
Code:
df -g | grep -v var| awk '$4+0 > 90{print "Filesystem", $NF,"over sized"}'
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