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Sort Decimal number in UNIX

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# 1  
Old 06-27-2013
Sort Decimal number in UNIX
Hello Everyone,

In one of my script, I would like to sort the decimal numbers.

For e.g.

If I have numbers like
Code:
1.0 1.1 1.2 2.0 2.1 3.0 4.0 5.0 6.0 7.0 7.1 7.10 7.2 7.3 7.4 7.5 7.6 7.7 7.8 7.9

I would like to sort them

Code:
1.0 1.1 1.2 2.0 2.1 3.0 4.0 5.0 6.0 7.0 7.1 7.2 7.3 7.4 7.5 7.6 7.7 7.8 7.9 7.10

that means, 1.10 is greater that 1.2.

Can you please help me out to achieve this.

Kind Regards,
Sachin

Moderator's Comments:
Mod Comment Use code tags, thanks; see PM.
Last edited by zaxxon; 06-27-2013 at 05:50 AM.. Reason: code tags
# 2  
Old 06-27-2013
Where are these numbers stored? If they appear line by line in a file, you can use sort command.

Code:
sort -nk1,1 filename

If you have the list of numbers in a variable (say LIST), you can use

Code:
echo $LIST | tr " " "\n" | sort -nk1,1


Please discard this solution. I read the problem as "sorting decimals" from the subject. The problem is slightly different here.
Last edited by krishmaths; 06-27-2013 at 05:56 AM.. Reason: Wrong solution
# 3  
Old 06-27-2013
Try this:
Code:
sort -t. -k1,1n -k2,2n

If it's one line, you'll have to split it first:
Code:
tr ' ' '\n' < file

# 4  
Old 06-27-2013
try..

Code:
 
cat filename| tr ' ' '\n' | sort -t. -nk1,1 -k2,2|tr '\n' ' '

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