awk : finding and formatting


 
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# 1  
Old 06-27-2013
awk : finding and formatting

Hi ,

I was trying to find files of a particular date and did that but then I also wanted to format a field based on some condition so had put another if else in awk.
Now it is getting the files of particular date or also the files which are matching that if else condition.

Code:
find . -name "*" -ctime -6 | xargs cat | grep -E -v ^fileName\|^\([0-9]\) | awk -v DATE="${CURR_DATE}" -v DATE_LOG="$DATE_SYS" '
        BEGIN {
                FS = ";"
                OFS = ";"
                CONVFMT = "%.9g"
                OFMT = "%.9g"
        }
       (substr($0,12,8)==DATE)  
       {  
         if(substr($0,5,6)=="ABCR01") 
               {IN=1}
         else 
               {IN=2}
        } 
        {
                clef = "2-PARSING_ERROR;" DATE ";" DATE_LOG ";"
                substr ( $0, 12, 8) ";" substr ( $0, 5, 6 ) ";"IN";NS;NS;" $3
                tab[clef]++
        }
        END {
                for (clef in tab)
                {
                        print tab[clef],clef
                }
        }
'

Now its giving returning the output if the file is of date "DATE" or if the files has substring matching ABCR01..
My motive is to find the files matching the date and to populate "IN" based on the condition.

Also, if i don't want to find files based on date then how to put the if else mechanism so that it doesnot select files for ABCR01 but populate IN as expected.

Please help

Regards

Abhinav

---------- Post updated at 02:10 PM ---------- Previous update was at 12:44 PM ----------

Code:
find . -name "*" -ctime -6 | xargs cat | grep -E -v ^fileName\|^\([0-9]\) | awk -v DATE="${CURR_DATE}" -v DATE_LOG="$DATE_SYS" '
        BEGIN {
                FS = ";"
                OFS = ";"
                CONVFMT = "%.9g"
                OFMT = "%.9g"
        }
       (substr($0,12,8)==DATE)  
        {
                clef = "2-PARSING_ERROR;" DATE ";" DATE_LOG ";"
                substr ( $0, 12, 8) ";" substr ( $0, 5, 6 ) ";"IN";NS;NS;" $3
                tab[clef]++
        }
        END {
                for (clef in tab)
                {
                        print tab[clef],clef
                }
        }
' |  awk -F";" 
     'BEGIN {OFS=";"} 
     {if(substr($0,5,6)=="SMSR01") 
        {IN=1}
      else 
        {IN=2}} 
  { print $1,$2,$3,$4,$5,IN,"ALL","N/A",$NF}'

Solved my query like this.

Regards

Abhinav

Last edited by abhi1988sri; 06-27-2013 at 05:50 AM..
# 2  
Old 07-01-2013
Wow, xargs cat is just a delay. find could match name patterns. ctime is not very reliable, usually date in name or mtime is a good hook, but for precision you need to use -newer and ! -newer or the like. Glad you solved the awk part, surprised to see it in two pieces.
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